Question 327335
The sum of three consecutive odd integers equals one less than for times the smallest integer.
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let the smallest odd integer be x
next will be x+2
third will be x+4
Their sum = x+x+2+x+4= 3x+6.............1
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smallest integer = x
4 times the number = 4x
1 less than 4 times the number 
4x-1....................................2

3x+6=4x-1
add -6 to both sides
3x+6-6=4x-1-6
3x=4x-7
add -4x to both sides
3x-4x=4x-4x-7
-x=-7
divide both by -1
-x/-1 = -7/-1
x=7
the numbers are 7, 9, 11