Question 327174
{{{(6x^3 + 13x^2 -11x-15)/(3x^2-x-3)}}}
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First term:{{{2x}}}
{{{2x(3x^2-x-3)=6x^3-2x^2-6x}}}
Subtract this product from the original polynomial to get the remainder.
{{{(6x^3 + 13x^2 -11x-15)-(6x^3-2x^2-6x)=15x^2-5x-15}}}
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Second term:{{{5}}}
{{{5(3x^2-x-3)=15x^2-5x-15}}}
Subtract this product from the remainder to get the new remainder.
{{{(15x^2-5x-15)-(15x^2-5x-15)=0}}}
Now gather the terms.
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{{{(6x^3 + 13x^2 -11x-15)/(3x^2-x-3)=(2x+5)}}}