Question 327242
<font face="Garamond" size="+2">


Let *[tex \Large x] represent the smaller of the two integers.  Then the other one has to be *[tex \Large x\ +\ 1].


The product, *[tex \Large x(x\ +\ 1)] is five more than their sum *[tex \Large x\  +\ x\ +\ 1\ +\ 5]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ x\ =\ 2x\ +\ 6]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ x\ -\ 6\ =\ 0]


Factor and solve the quadratic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>