Question 327231
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Area of the outer circle minus the area of the hole in the middle:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A_{ring}\ =\ \pi{R^2}\ -\ \pi{r^2}\ =\ \pi(R^2\ -\ r^2)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \pi((12)^2\ -\ (5)^2)]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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