Question 36626
{{{f(x)=x^2 + 2}}}
Since this is an exponential function it is a function of a parabola.
We can find our points of the graph by creating a table of values.
We take our exponential expression {{{x^2 + 2}}} and substitute values for x.
We should find 7 points: the vertex and 6 corresponding points.
If x = 0 then y = 2 (vertex)
If x = 1 then y = 3
If x = -1 then y = 3
If x = 2 then y = 6
If x = -2 then y = 6
If x = 3 then y = 11
If x = -3 then y = 11
Then we plot the points...
{{{ graph( 300, 200, -8, 8, -3, 15, x^2 + 2) }}}
This is what the parabola will look like...
I hope this helps
Good Luck!