Question 327211
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Use the difference of two cubes factorization.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^3\ -\ b^3\ =\ (a\ -\ b)\left(a^2\ +\ 2ab\ +\ b^2\right)]


Hint: *[tex \Large 64\ =\ 4^3]


For future reference:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^3\ \pm\ b^3\ =\ (a\ \pm\ b)\left(a^2\ \mp\ 2ab\ +\ b^2\right)]


To remember the signs, Use San Diego Padres, SDP, Same Different Plus.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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