<PRE><B>Question 327135</B>
F(t)= 270 - 70 log5 (4t + 1),where t is measured in years. How much space is left when t = 1? 
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F(1) = 270 - 70*log5(4+1)
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F(1) = 270 - 70*log5(5)
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Note: log5(5) is 1 because 5^1 = 5.
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F(1) = 270-70
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F(1) = 200
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Cheers,
Stan H.
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