Question 327014
y^8 - 16y^5
Factor out common terms.
{{{y^8y - 16y^5=y^9-16y^5}}}
{{{y^8y - 16y^5=y^5(y^4-16)}}}
The term in parenthese is the difference of two squares,
{{{y^8y - 16y^5=y^5(y^2+4)(y^2-2)}}}
The final term is also a difference of two squares,

{{{y^8y - 16y^5=y^5(y^2+4)(y-sqrt(2))(y+sqrt(2))}}}