Question 326980
Complete the square to put into vertex form, {{{y=a(x-h)^2+k}}}, where (h,k) is the vertex.
{{{f(x)=3x^2-2x}}}
{{{f(x)=3(x^2-(2/3)x)}}}
{{{f(x)=3(x^2-(2/3)x+(1/9))-3/9}}}
{{{f(x)=3(x-1/3)^2-1/3}}}
The vertex is (1/3,-1/3).
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(1/3,-1/3,.2),graph(300,300,-5,5,-5,5,3x^2-2x))}}}