Question 326973
Thanks for thanking me in advance! Haha, that's cute ^.^

Since this is a word problem, you want to write out the equations. Let L equal the length of the garage. Let W equal the width of the garage. "A rectangular garage is 9 feet longer than it is wide": {{{L=W+9}}}. Now for the next equation. You know {{{Area=length*width}}}, so {{{630=L*W}}}. You can plug the first equation into the second to get {{{630=(W+9)*W}}}. After you distribute the w you get {{{630= W^2+9W}}}. Subtract 630 from both sides to get {{{0=W^2+9w-630}}}. You can plug this into the quadratic formula to get the value of W: {{{W=(-b+-sqrt(b^2-4ac))/(2a)}}}. Let a=1, b=9, and c=-630 (these are just the numbers in front of the terms =). After you plug the numbers into the quadratic equation and solve, you get {{{W=21}}} or {{{W=-30}}}. Since the length can't be negative, we know that {{{W=21}}}. You can find the value of L by plugging {{{W=21}}} into {{{L=W+9}}} or {{{630=L*W}}}. Since it doesn't matter which equation you use, you might as well use the easier equation! I choose to plug {{{W=21}}} into {{{L=W+9}}}. After solving for L you get {{{L=30}}}. You can check that these lengths will give an area of 630 square feet for the garage: 21*30=630 square feet! The sides of the garage are thus 21 feet width by 30 feet long. If you need anymore help from me, you can visit me at my website: http://myonlinetutor.webs.com! Become a member \(^o^)/!!! Thanks in advance, haha XD