Question 327003
Through the elimination method, you can cancel out a variable. This will leave you with one variable in the equation. You can then solve the equation to find the value of the variable. Okay, lets start! =)

I will try to get rid of the x. I'll call {{{0.3x-0.2y=4}}} equation #1, and {{{0.2x+0.5y=-3}}} equation #2. If we want to get rid of the x variable, we have to make sure the number in front of the x terms in the two equations are the same. Right now they both have different numbers in front of them. Multiply equation #1 by 2 and equation #2 by 3 to get {{{0.6x-0.4y=8}}} and {{{0.6x+1.5y=-9}}}. Notice that now we have 0.6 in front of the x terms, perfect! ^0^ Lets subtract the second equation from the first: {{{(0.6x-0.4y)-(0.6x+1.5y)=8-(-9))}}}. That becomes {{{-1.9y=17}}}. Divide both sides by -1.9 to get the y by itself: {{{y=-8.9}}}. You can pluy this back into either of the given equations to find x. I'll just choose equation #1 to plug into. It doesn't matter =) When we plug in y=-8.9, we get {{{0.3x-0.2y=4}}} becomes{{{0.3x-0.2(-8.9)=4}}}. Solving for x gives you x= 7.4! Now that you have found that y=-8.9 and x=7.5, you are done! 
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