Question 327012
6x2 + 17x + 12 
this is of the form ax^2 + bx +c
the roots x1,x2 will be
{{{ x=(-b+-sqrt(b^2-4ac))/2a}}}
{{{ x1=(-b+sqrt(b^2-4ac))/2a}}}
{{{ x1=(-17+sqrt(17^2-4*6*12))/2*6}}}
x1=-1.33
{{{ x2=(-17-sqrt(17^2-4*6*12))/2*6}}}
x2=-1.5