Question 326889
Convert to vertex form by completing the square,
{{{f(x)=4x^2-x+2}}}
{{{f(x)=4(x^2-(1/4)x)+2}}}
{{{f(x)=4(x^2-(1/4)x+1/64)+2-4/64}}}
{{{f(x)=4(x-1/8)^2+128/64-4/64}}}
{{{f(x)=4(x-1/8)^2+31/16}}}
The vertex is (1/8,31,16).
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{{{drawing(300,300,-2,2,-1,3,grid(1),circle(1/8,31/16,.1),graph(300,300,-2,2,-1,3, 4x^2-x+2))}}}