Question 326646
{{{graph(300,300,-10,10,-10,10,9/(x^2+7x+10)-5/(x+2)+3/(x+5))}}}
.
.
.
I re-arranged the equation to be,
{{{f(x)=9/(x^2+7x+10)-5/(x+2)+3/(x+5))=0}}}
As you can see, f(x) never equals zero.
No solution.