Question 326637
The interest formula is 

{{{A=P(1+r/n)^(nt)}}}

Now, in this case, we want to end up with 4,000. We are given n, r, and A.

We have to solve for P, the initial amount invested.

n=the number of times compounded in a year. In this case, n=12

r=.03

A=4000

{{{4000=P(1+.03/12)^(12*5)}}}

{{{4000=P(1.0025)^(60)}}}

{{{P=4000/(1.0025)^60}}}

{{{P=3443.48}}}

We would have to invest 3443.48 in order to get 4000 at the end of 5 years at 3% interest compounded monthly.

If you encounter subsequent problems of this nature, look at what you're given and sub them into the formula, then solve for the unknown.