Question 326765
It's a quadratic equation with mixed number coefficients.
First, make the mixed numbers into fractions.
{{{6+2/3=20/3}}}
{{{1+1/3=4/3}}}
{{{-(20/3)x^2+(4/3)x=2/3}}}
Now multiply by -(3/2) to get rid of fractions and get to simplest form,
{{{10x^2-2x=-1}}}
{{{10x^2-2x+1=0}}}
Use the quadratic formula,
{{{x = (2 +- sqrt( 2^2-4*10*1 ))/(2*10) }}}
{{{x = (2 +- sqrt( 4-40 ))/20 }}}
{{{x = (2 +- sqrt( -36 ))/20 }}}
{{{x = (2 +- 6i)/20 }}}
{{{highlight(x = (1 +- 3i)/10 )}}}
where {{{i=sqrt(-1)}}}