Question 326761
PErpendicular lines have slopes that are negative reciprocals.
{{{m1*m2=-1}}}
{{{(1/2)*m2=-1}}}
{{{m2=-2}}}
Your new equation will have the form,
{{{y=-2x+b}}}
Use the point (0,0) to solve for {{{b}}}.
{{{0=0+b}}}
{{{b=0}}}
{{{highlight(y=-2x)}}}
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{{{graph(300,300,-5,5,-5,5,(1/2)x-2,-2x)}}}