Question 326720
Let (7x+1)/(x+1)(x-2) = m/(x + 1) + n/(n - 2), m and n being integers.
Multiplying by (x+1)(x-2) on both sides of equality, we get
(7x+1) = m(x - 2) + n(x + 1)
=> 7x + 1 = (m + n)x + n - 2m
Equating the coefficients of x and the constant terms on both sides of equality, we get
m + n = 7
-2m + n = 1
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(subtracting) 3m = 6
m = 2
Hence, n = 5
Hence, 
(7x+1)/(x+1)(x-2) = 2/(x+1) + 5/(x-1)