Question 326633
{{{(x-10)(x-6) = -3}}}
Use the FOIL method,
{{{x^2-6x-10x+60=-3}}}
{{{x^2-16x+60=-3}}}
{{{x^2-16x+63=0}}}
{{{(x-7)(x-9)=0}}}
Two solutions:
{{{x-7=0}}}
{{{highlight(x=7)}}}
.
.
.
{{{x-9=0}}}
{{{highlight(x=9)}}}