Question 326585
The solution set is  a set of x-values that satisfy x^2 - 3x - 10 <= 0.  It will be an interval.

Factor x^2 - 3x - 10  into (x - 5)*(x + 2), because 2 * (-5) = -10 and 2 - 5 = -3.

First find x values such that (x - 5)*(x + 2) <= 0.

for (x - 5)   we see for x <= 5  (x - 5) <= 0
for (x - 5)   we see for x > 5  (x - 5) > 0

for (x + 2)   we see for x <= -2 (x + 2) <= 0
for (x + 2)   we see for x > -2 (x + 2) > 0


draw a line    -----------------0++++++++++++++++++++
                                5
               --------0+++++++++++++++++++++++++++++
                      -2

(x-5)*(x+2) :  ++++++++0--------0++++++++++++++++++++




so  (x-5)*(x+2) <= 0 when  -2 <= x <= 5

Solution set :  -2 <= x <=5