Question 326574


{{{(y+6)^2-75=0}}} Start with the given equation.



{{{(y+6)^2=0+75}}}Add {{{75}}} to both sides.



{{{(y+6)^2=75}}} Combine like terms.



{{{x+6=""+-sqrt(75)}}} Take the square root of both sides.



{{{y+6=sqrt(75)}}} or {{{y+6=-sqrt(75)}}} Break up the "plus/minus" to form two equations.



{{{y+6=5*sqrt(3)}}} or {{{y+6=-5*sqrt(3)}}}  Simplify the square root.



{{{y=-6+5*sqrt(3)}}} or {{{y=-6-5*sqrt(3)}}} Subtract {{{6}}} from both sides.



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Answer:



So the solutions are {{{y=-6+5*sqrt(3)}}} or {{{y=-6-5*sqrt(3)}}}.