Question 326544
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The same way you would eat an elephant.  One bite at a time.  Start with:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2x\ -\ 9}{4}\ <\ -9]


Multiply by 4


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ -\ 9\ <\ -36]


Add 9


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ <\ -27]


Multiply by *[tex \Large \frac{1}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ <\ -\frac{27}{2}]


Now do the other part.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2x\ -\ 9}{4}\ >\ 7]


Multiply by 4


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ -\ 9\ >\ 28]


Add 9


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ >\ 37]


Multiply by *[tex \Large \frac{1}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ >\ \frac{37}{2}]


In interval notation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(-\infty,-\frac{27}{2}\right)\ \small{\cup}\ \LARGE \left(\frac{37}{2},\infty\right)]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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