Question 326546
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If the hypotenuse is 13 and the legs differ by 7, then the legs measure 5 and 12 (common Pythagorean triple).  Use the Pythagorean Theorem *[tex \LARGE 13^2\ =\ x^2\ +\ (x\ -\ 7)^2] to verify (left as an exercise for the student)


In a right triangle, the area is simply *[tex \LARGE \frac{1}{2}ab] where *[tex \LARGE a] and *[tex \LARGE b] are the measures of the legs.  Hence: *[tex \LARGE \frac{1}{2}(5)(12)].


Do your own arithmetic (Cowboy up and do it in your head).


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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