Question 326467
First pick a coordinate system. 
Let North be positiive y.
Let East be positive x.
Then find the x,y components of each force.
"250 lbs 60 degrees N of E"=250(cos(60),sin(60))=(125,216.5)
"100 lbs 30 degrees N of W"=100(cos(150),sin(150))= (-86.6,50)
"200 lbs S"=200(0,-1)=(0,-200)
Then sum the x and y components to get the resultant.
(Fx,Fy)=(125,216.5)+(-86.6,50)+(0,-200)
(Fx,Fy)=(38.4,66.5)
You can find the resultant magnitude and direction,
{{{r=sqrt(38.4^2+66.5^2)=76.8}}}
{{{tan(theta)=66.5/38.4}}}
{{{theta=60}}}
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76.8 lbs 60 degrees North of East.
 act on an object. Find the direction and magnitude of the resultant force.