Question 326411
1.{{{7x+3y=12}}}
2.{{{3x+7y=6}}}
From eq. 1,
{{{3y=-7x+12}}}
{{{y=-(7/3)x+4}}}
Substitute into eq. 2,
{{{3x+7(-(7/3)x+4)=6}}}
{{{3x-(49/3)x+28=6}}}
{{{9x-49x+84=18}}}
{{{-40x=-66}}}
{{{highlight(x=33/20)}}}
Then using eq.1,
{{{231/20+3y=240/20}}}
{{{3y=9/20}}}
{{{highlight(y=3/20)}}}