Question 326344
let him cut squares of length x in.
rectangle 
length =14
width =11
..
the length after cutting the squares will be 14-2x
the breadth will be 11-2x
(14-2x)(11-2x)=80
154-28x-22x+4x^2 =80
4x^2-50x+154-80=0
4x^2-50x+74=0  ( divide by 2)
2x^2-25x+37=0
we have to find the roots of the equation x1,x2 
x1= {{{(25+sqrt(25^2-296))/4}}}
=10.87 in
x2={{{(25-sqrt(25^2-296))/4}}}
x2=1.71
CHECK
(14-2*1.71)(11-2*1.71)= 80.1 sq.in
so 1.71 side square has to be cut.
x1 is not valid