Question 326314
{{{4^(7x-2) = 17^(x + 1)}}}
{{{7x-2=log(4,(17^(x+1)))}}}
Change bases.
{{{7x-2=log(17,(17^(x+1)))/log(17,(4))}}}
{{{7x-2=(x+1)/log(17,(4))}}}
{{{(7x-2)log(17,(4))=x+1}}}}
{{{7*log(17,(4))x-2log(17,(4))=x+1}}}
{{{(7*log(17,(4))-1)x=1+2log(17,(4))}}}
{{{highlight(x=(2log(17,(4))+1)/(7*log(17,(4))-1))}}}
{{{x=0.816}}}