Question 326330
let width be x
length = 3x-5
Area = 78 sq. yards
{{{x(3x-5)=78}}}
{{{3x^2-5x=78}}}
add -78 to both sides
{{{3x^2-5x-78 =78-78}}}
{{{3x^2-5x-78=0}}}

the roots of the equation x1, x2 can be found out by the formula
{{{x1=(-b +sqrt(b^2-4ac))/2a}}}
a= 3 , b= -5 , c = -78
{{{x1=(-(-5) +sqrt((-5)^2-4*3*-78))/(2*3)}}}
x1=6  yards the width
length = 3x-5 = 3*6-5
=13 yards
x2= -4.3333
x2 is negative  so we ignore