Question 326300
{{{3t^2-3}}}
3 is common in both terms
{{{3((t)^2-1))}}}
{{{3((t)^2-(1^2))}}}
the above equation is of type {{{a^2-b^2=0}}}= {{{(a+b)(a-b)}}}
{{{3(t+1)(t-1)}}}

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