Question 326302
kx^2-10x+5=0
in the general equation ax^2+bx +c
for the roots to be equal
b^2-4ac=0
b=-10, a=k,c=5
..
(-10)^2-4*k*5 =0
100-20k=0
add 20k to both sides
{{{100-20k+20k=20k}}}
{{{100=20k}}}
{{{divide by 20}}}
{{{100/20=20k/20}}}
5=k