Question 326231
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There are 18 bills total, so you have a:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{8}{18}] chance of drawing $1.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4}{18}] chance of drawing $2.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3}{18}] chance of drawing $5.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2}{18}] chance of drawing $10.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{18}] chance of drawing $100.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 1\ \times\ 8\ +\ 2\ \times\ 4\ +\ 5\ \times\ 3\ +\ 10\ \times\ 2\ +\ 100\ \times\ 1\ =\ 151]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{151}{18}\ \approx\ $8.39]


is the average payout per draw, but you pay $20 to play each time, so your expected payout per play is


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -20\ +\ 8.39\ =\ -11.61]


Ok, I'll play IF I get to be the dealer.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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