Question 326192
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The smallest number is *[tex \Large a]


The next larger number is *[tex \Large b\ =\ a\ +\ 3]


The largest number is *[tex \Large c\ =\ b\ +\ 6\ =\ a\ +\ 3\ +\ 6\ =\ a\ +\ 9]


The median is *[tex \Large b\ =\ a\ +\ 3] by definition.


The average is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{a\ +\ b\ +\ c}{3}\ =\ \frac{a\ +\ a\ +\ 3\ +\ a\ +\ 9}{3}\ =\ \frac{3a\ +\ 12}{3}\ =\ a\ +\ 4]


The average minus the median is then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (a\ +\ 4)\ -\ (a\ +\ 3)\ =\ 1]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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