Question 326128
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If you put the given equation into slope-intercept form *[tex \LARGE (y\ =\ mx\ +\ b)] then you will be able to determine the slope of the given line by inspection.  Then use:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \parallel\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ m_2]


to determine the slope of the desired parallel line.  Then use the point-slope form to write an equation of the desired line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the given/calculated slope.  Finally, arrange your equation into slope intercept form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ mx\ +\ (y_1\ -\ mx_1)]


Note:  *[tex \Large y_1\ -\ mx_1\ =\ b]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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