Question 326111
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I'm going to presume that you meant:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3}{7}x\ >\ -3]


rather than


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3}{7x}\ >\ -3]


which has a very different outcome.


Going on that presumption, your answer of 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ >\ -7] is correct.


That simply means that x can be any real number so long as it is larger than -7:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(-7,\infty\right)]


Note that your inequality symbol was *[tex \Large >] rather than *[tex \Large \geq], so the right end of your interval is a parenthesis indicating non-inclusive.  Had it been *[tex \Large \geq], you would have had a [ instead of a (.  The other end is *[tex \Large \infty] so the end marker is ALWAYS open, that is ).


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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