<PRE><B>Question 326046</B>
Find exact values for all real/complex numbers solutions to the equation
x^4+x^3-2x^2-6x-4=0
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Since f(-1) = 0, x= -1 is a solution.
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Use synthetic division to help find other solutions:
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-1)....1....1....-2....-6....-4
.......1.....0.....-2....-4....|.0

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Quotient: x^3 -2x - 4 = 0
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Since f(2) = 0, x = 2 is a solution
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2)....1....0....-2....-4
.......1....2.....2...|..0

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Quotient: x^2 + 2x + 2

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Use the quadratic formula to find the complex solutions.

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Cheers,
Stan H.</PRE>