Question 325940
1.{{{2x^2-y^2=1}}}
2.{{{x^2-2y^2= -1}}}
Multiply eq. 2 by -2 and add to eq. 1,
{{{2x^2-y^2-2x^2+4y^2=1+2}}}
{{{3y^2=3}}}
{{{y^2=1}}}
{{{y=0 +- 1}}}
Solve for x in each case of y using either equation.
{{{y=1}}}
{{{2x^2-1=1}}}
{{{2x^2=2}}}
{{{x=0 +- 1}}}
.
.
.
{{{y=-1}}}
{{{2x^2-1=1}}}
{{{x= 0 +- 1}}}
.
.
.
(-1,1)
(-1,-1)
(1,1)
(1,-1)
.
.
.
{{{drawing(300,300, -3,3,-3,3, grid(1),
circle(-1,1,.12),circle(-1,-1,.12),circle(1,-1,.12),circle(1,1,.12),
graph(300,300,-3,3,-3,3, sqrt(2x^2-1)),
graph(300,300,-3,3,-3,3,-sqrt(2x^2-1)),
graph(300,300, -3,3,-3,3, sqrt((x^2+1)/2)),
graph(300,300,-3,3,-3,3,-sqrt((x^2+1)/2)))}}}