Question 325915
<pre><b>
There are two methods to do this problem:

Method 1:

Here are all 52 cards in a deck:
<font color = "red">

A&#9829;   2&#9829;   3&#9829;   4&#9829;   5&#9829;   6&#9829;   7&#9829;   8&#9829;  9&#9829;  10&#9829;  J&#9829;  Q&#9829;  K&#9829; 
A&#9830;   2&#9830;   3&#9830;   4&#9830;   5&#9830;   6&#9830;   7&#9830;   8&#9830;  9&#9830;  10&#9830;  J&#9830;  Q&#9830;  K&#9830;</font>
A&#9824;   2&#9824;   3&#9824;   4&#9824;   5&#9824;   6&#9824;   7&#9824;   8&#9824;  9&#9824;  10&#9824;  J&#9824;  Q&#9824;  K&#9824;</font>  
A&#9827;   2&#9827;   3&#9827;   4&#9827;   5&#9827;   6&#9827;   7&#9827;   8&#9827;  9&#9827;  10&#9827;  J&#9827;  Q&#9827;  K&#9827;  

The ones which fit that description as either a heart or a picture card 
(king, queen or jack), are these 22 cards:
<font color = "red">
A&#9829;   2&#9829;   3&#9829;   4&#9829;   5&#9829;   6&#9829;   7&#9829;   8&#9829;  9&#9829;  10&#9829;  J&#9829;  Q&#9829;  K&#9829; 
                                                J&#9830;  Q&#9830;  K&#9830;</font>
                                                J&#9824;  Q&#9824;  K&#9824;  
                                                J&#9827;  Q&#9827;  K&#9827;
 
So the answer is 22 out of 52 or {{{22/52}}} which reduces to {{{11/26}}}.

Method 2:

By formula: P(A or B) = P(A) + P(B) - P(A and B)

P(<font color = "red">&#9829;</font> or FACE) = P(<font color="red">&#9829;</font>) + P(FACE) - P(<font color="red">&#9829;</font> and FACE)
             =  {{{13/52}}}  +   {{{12/52}}}   -   {{{3/52}}} 
             =  {{{(13+12-3)/52}}}
             =  {{{22/52}}}
             =  {{{11/26}}}   

Edwin</pre>