<PRE><B>Question 325925</B>
|(x+2)/(2)|=3x-3

(x+2)/(2)=\(3x-3)

(x+2)/(2)=3x-3

x+2=6x-6

-5x+2=-6

-5x=-8

x=(8)/(5)

(x+2)/(2)=-(3x-3)

(x+2)/(2)*2=-(3x-3)*2

x+2=-(3x-3)*2

x+2=-6x+6

x+2+6x=6

7x+2=6

7x=-2+6

7x=4

(7x)/(7)=(4)/(7)

x=(4)/(7)

x=(8)/(5),(4)/(7)

x=(8)/(5)</PRE>