Question 325908
x+y=5_x-5y=-9

Multiply the first equation by -1 to make the coefficients of x have opposite signs.
-(x+y)=-(5)_x-5y=-9

Multiply -1 by the 5 inside the parentheses.
-(x+y)=-5_x-5y=-9

Multiply -1 by each term inside the parentheses.
-x-y=-5_x-5y=-9

Add the two equations together to eliminate x from the system.
  x-5y=-9_<U>- x-y=-5<u>_  -6y=-14

Divide each term in the equation by -6.
y=(7)/(3)

Substitute the value found for y into the original equation to solve for x.
-x-((7)/(3))=-5

Multiply -1 by each term inside the parentheses.
-x-(7)/(3)=-5

Move all terms not containing x to the right-hand side of the equation.
-x=-(8)/(3)

Multiply -x by -1 to get x.
x=-(8)/(3)*-1

Divide each term in the equation by -1.
x=(8)/(3)

This is the final solution to the independent system of equations.
y=(7)/(3)_x=(8)/(3)