Question 325893
4x-2y=16_5x+7y=1

Multiply each equation by the value that makes the coefficients of y equal.  This value is found by dividing the least common multiple of the coefficients of y by the current coefficient.  In this case, the least common multiple is 14.
7*(4x-2y=16)_2*(5x+7y=1)

Multiply each equation by the value that makes the coefficients of y equal.  This value is found by dividing the least common multiple of the coefficients of y by the current coefficient.  In this case, the least common multiple is 14.
7*(4x-2y)=7(16)_2*(5x+7y)=2(1)

Multiply 7 by each term inside the parentheses.
7*(4x-2y)=112_2*(5x+7y)=2(1)

Multiply 7 by each term inside the parentheses.
(28x-14y)=112_2*(5x+7y)=2(1)

Remove the parentheses around the expression 28x-14y.
28x-14y=112_2*(5x+7y)=2(1)

Multiply 2 by each term inside the parentheses.
28x-14y=112_2*(5x+7y)=2

Multiply 2 by each term inside the parentheses.
28x-14y=112_(10x+14y)=2

Remove the parentheses around the expression 10x+14y.
28x-14y=112_10x+14y=2

Add the two equations together to eliminate y from the system.
10x+14y=2_<U>28x-14y=112<u>_38x    =114

Divide each term in the equation by 38.
x=3

Substitute the value found for x into the original equation to solve for y.
28(3)-14y=112

Multiply 28 by each term inside the parentheses.
84-14y=112

Move all terms not containing y to the right-hand side of the equation.
-14y=28

Divide each term in the equation by -14.
y=-2

This is the final solution to the independent system of equations.
x=3_y=-2