Question 325879
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Let *[tex \Large d] represent the distance between the two cities.  Let *[tex \Large t] represent the amount of time she drove 50 mph.  Then since 4 hours 24 minutes equals 4.4 hours, *[tex \Large 4.4\ -\ t] represents the amount of time driven at 60 mph.


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ 50t]


describes the outbound trip and 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ 60(4.4\ -\ t)]


describes the inbound trip, and, unless somebody picked Amity up and moved it while she was on the road or in Belleville, *[tex \Large d\ =\ d].  Therefore:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 50t\ =\ 60(4.4\ -\ t)]


Solve for *[tex \Large t] and then multiply *[tex \Large 50\ \times\ t] to calculate *[tex \Large d]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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