Question 325862
This is a difference of two squares which factors like this,
{{{Z^2-A^2=(Z+A)(Z-A)}}}
In this case,
{{{Z^2=25y^2}}}
{{{Z=5y}}}
.
.
.
{{{A^2=16}}}
{{{A=4}}}
So then,
{{{25y^2-16=(5y-4)(5y+4)}}}