Question 325796
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As *[tex \Large x] gets close to -9 from the right, *[tex \Large x] will be a negative number whose absolute value is going to be a little smaller than 9, hence *[tex \Large x^2] is going to be a little smaller than 81, and therefore *[tex \Large x^2\ -\ 81] becomes a very small negative number.  1 divided by a very small negative number is a very large negative number.


Using similar logic:


As *[tex \Large x] gets close to -9 from the left, *[tex \Large x^2\ -\ 81] becomes a very small positive number.  1 divided by a very small positive number is a very large positive number.


As *[tex \Large x] gets close to +9 from the left, *[tex \Large x^2\ -\ 81] becomes a very small negative number.  1 divided by a very small negative number is a very large negative number.


As *[tex \Large x] gets close to +9 from the left, *[tex \Large x^2\ -\ 81] becomes a very small positive number.  1 divided by a very small positive number is a very large positive number.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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