Question 325799
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(8,9\right)]. So this means that {{{x[1]=8}}} and {{{y[1]=9}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(10,-3\right)].  So this means that {{{x[2]=10}}} and {{{y[2]=-3}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-3-9)/(10-8)}}} Plug in {{{y[2]=-3}}}, {{{y[1]=9}}}, {{{x[2]=10}}}, and {{{x[1]=8}}}



{{{m=(-12)/(10-8)}}} Subtract {{{9}}} from {{{-3}}} to get {{{-12}}}



{{{m=(-12)/(2)}}} Subtract {{{8}}} from {{{10}}} to get {{{2}}}



{{{m=-6}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(8,9\right)] and *[Tex \LARGE \left(10,-3\right)] is {{{m=-6}}}