Question 325777
To find the x-intercept, let y = 0 and solve for x.

y + 12 = x^2 + x

Let y = 0

0 + 12 = x^2 + x

12 = x^2 + x

Subtract 12 from both sides.

0 = x^2 + x - 12

We now factor the quadratic equation.

0 = (x - 3)(x + 4)

Set each factor to zero and solve for x.

x - 3 = 0

x = 3

x + 4 = 0

x = -4

The x-intercepts are x = 3 and x = -4.

Did you follow?

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By the way, if you ever need to find the y-intercepts, let x = 0 and solve for y.