Question 325732
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The sum of the measures of the angles of any triangle is *[tex \LARGE 180^\circ].  Therefore, in a right triangle, where one of the angles measures *[tex \LARGE 90^\circ], the sum of the other two angles must be *[tex \LARGE 180^\circ\ -\ 90^\circ\ =\ 90^\circ].


Hence in your triangle,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(6x\ -\ 10\right)\ +\ \left(2x\ -\ 4\right)\ =\ 90]


Solve for *[tex \LARGE x] and then substitute back into *[tex \LARGE 6x\ -\ 10] and *[tex \LARGE 2x\ -\ 4].  Report the largest value.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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