Question 37725
Simplify
(b^c + 7bc - 3)- (12b^c - 2bc + 5)
This is simply a matter of combining like terms.
Remember pos. and neg. symbols remain with their respective variables.
We distribute the negative symbol in the second set.
So...
{{{b^c+7bc-3-12b^c+2bc-5}}}
Can be combined as...
{{{b^c-12b^c+7bc+2bc-3-5}}}
becomes...
{{{-11b^c+9bc-8}}}
This is the most this problem can be simplified
Good Luck!