Question 325625
{{{(x - 2)(2x + 8)(3x + 9) = 0}}}
a 2 and 3 can be factored out
{{{(x - 2)2(x + 4)3(x + 3) = 0}}}
{{{6(x - 2)(x + 4)(x + 3) = 0}}}
set each = to 0
{{{6(x - 2)=0}}}
{{{highlight(x=2)}}}
{{{(x + 4)=0}}}
{{{highlight(x=-4)}}}
{{{(x + 3)=0}}}
{{{highlight(x=-3)}}}
x={-4,-3,2}