Question 325519
{{{70.3=741*ln(5x-1)}}}
{{{ln(5x-1)=70.3/741}}}
{{{5x-1=e^(70.3/741)}}}
{{{5x=1+e^(70.3/741)}}}
{{{x=(1+e^(70.3/741))/5}}} or approximately,
{{{x=0.4199}}}