Question 325499


{{{(15a+35)/(12a^2+28a)}}} Start with the given expression.



{{{(5(3a+7))/(12a^2+28a)}}} Factor {{{15a+35}}} to get {{{5(3a+7)}}}.



{{{(5(3a+7))/(4a(3a+7))}}} Factor {{{12a^2+28a}}} to get {{{4a(3a+7)}}}.



{{{(5*highlight((3a+7)))/(4a*highlight((3a+7)))}}} Highlight the common terms. 



{{{(5*cross((3a+7)))/(4a*cross((3a+7)))}}} Cancel out the common terms. 



{{{5/(4a)}}} Simplify. 



So {{{(15a+35)/(12a^2+28a)}}} simplifies to {{{5/(4a)}}}.



In other words, {{{(15a+35)/(12a^2+28a)=5/(4a)}}}